31 May 2013 @ 11:27 PM 
 

補救教學(7)—擲2粒骰子

 

補救教學(7)—擲2粒骰子


擲二粒公正骰子，

(1)求點數和為6的機率

(2)在點和6的條件下，求出現至少一個偶數點的機率

(詳解):

(1)點和為6的可能是 (1,5), (2,4), (3,3), (4,2), (5,1)五種情形

而樣本空間有6×6個元素,

得答案

(2)設A為點和6的事件

B為至少出現一個偶數點的事件，

今分母P(A)=


分子為P(點和6且最少有一個偶數點)

則所求為

 

2粒骰子點和列表:

2

3

4

5

6

7

8

9

10

11

12

1

2

3

4

5

6

5

4

3

2

1
Tags Categories: 數學 Posted By: 我是大富翁
Last Edit: 04 Jun 2013 @ 12 23 AM

E-mail • Permalink
Previous: Next:
 

Responses to this post » (18 Total)

 

Sorry, but comments are now closed. Check out another post and speak up!

Comment Meta:
RSS Feed for comments
 

Leave A Comment ...

 

XHTML:
You can use these tags: <a href="" title=""> <abbr title=""> <acronym title=""> <b> <blockquote cite=""> <cite> <code> <del datetime=""> <em> <i> <q cite=""> <strike> <strong>
\/ More Options ...
Last 50 Posts
Back
Back
Register an account
Change Theme...
  • Role »
  • Posts »
  • Comments »
Change Theme...
  • VoidVoid (Default)
  • LifeLife
  • EarthEarth
  • WindWind
  • WaterWater
  • FireFire
  • LiteLightweight
  • No Child Pages...
  • No Child Pages...
  • No Child Pages...