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The opinions expressed herein are my own personal opinions and do not represent anyone else's view in any way, including those of my employer.
© Copyright 2013
The opinions expressed herein are my own personal opinions and do not represent anyone else's view in any way, including those of my employer.
© Copyright 2013
補救教學(9)—使機率高達0.999
一校隊王顥投籃，他的實力統計是平均每5球命中4球，
問他應該要連投幾球，才會使至少命中一發的機率大於0.999?
(詳解):
王顥的每一次投球的命中率=0.8，不命中的機率=0.2
假設教練小蔡老師要求他至少命中一發的水準必須>0.999
(不必百分之百，也不可能百分之百，永遠不會miss)，
設他連投n球，至少命中一發的機率為p，題意即要求出n，使
p>0.999
此即-p<-0.999,
兩邊同加1, 則1-p<0.001,
而1-p正是p的否定，也就是說，1-p是他連投n發，而這n發通通摃龜之機率，
所以有
答案:他至少須要連發5發才辦得到。
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