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The opinions expressed herein are my own personal opinions and do not represent anyone else's view in any way, including those of my employer.
© Copyright 2013
The opinions expressed herein are my own personal opinions and do not represent anyone else's view in any way, including those of my employer.
© Copyright 2013
補救教學(7)—擲2粒骰子
擲二粒公正骰子，
(1)求點數和為6的機率
(2)在點和6的條件下，求出現至少一個偶數點的機率
(詳解):
(1)點和為6的可能是 (1,5), (2,4), (3,3), (4,2), (5,1)五種情形
而樣本空間有6×6個元素,
得答案
(2)設A為點和6的事件
B為至少出現一個偶數點的事件，
今分母P(A)=
分子為P(點和6且最少有一個偶數點)
則所求為
2粒骰子點和列表:
|
2 |
3 |
4 |
5 |
6 |
7 |
8 |
9 |
10 |
11 |
12 |
|
1 |
2 |
3 |
4 |
5 |
6 |
5 |
4 |
3 |
2 |
1 |
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