21 May 2013 @ 8:23 AM 
 

進階教學(11)—-7個傻8個呆9個壞

 
進階教學(11)—7個傻8個呆9個壞
上課教材 3-1 的【自我實力評量】第4題:

10個男人中，7個傻，8個呆，9個壞;
(1)又傻又呆的最少_____人
(2)又傻又呆又壞的最少____人

(詳解)
設
7個傻的所成集合為A
8個呆的所成集合為B
9個壞的所成集合為C,
(1)
設
 
由

 

且

得

 

即

 

 

 

 

(2)
設
由
與
得
此即

  


 

Tags Categories: 數學 Posted By: 我是大富翁
Last Edit: 24 May 2013 @ 02 01 PM

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